Question

find the following product and write the result in standard form, a + bi.\\((-8 + 6i)(8 + i)\\)\\((-8 + 6i)(8 + i) = \square\\)

Explanation:

Step1: Apply FOIL method

$(-8)(8) + (-8)(i) + (6i)(8) + (6i)(i)$

Step2: Calculate each term

$-64 -8i +48i +6i^2$

Step3: Substitute $i^2=-1$

$-64 +40i +6(-1)$

Step4: Simplify real terms

$-64 -6 +40i = -70 +40i$

Answer:

$-70 + 40i$