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Question
find $p(q(-2))$ for the functions $p(x) = x^2 + 1$ and $q(x) = \sqrt{x + 2}$. select one: a. $-5$ b. $-1$ c. $5$ d. $1$
Step1: Calculate $q(-2)$
Substitute $x=-2$ into $q(x)$:
$q(-2)=\sqrt{-2 + 2}=\sqrt{0}=0$
Step2: Calculate $p(q(-2))$
Substitute $q(-2)=0$ into $p(x)$:
$p(0)=0^2 + 1=1$
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D. 1