Question

find the length of side ( x ) to the nearest tenth.

Explanation:

Step1: Identify trigonometric ratio

We use sine: $\sin(\theta)=\frac{\text{opposite}}{\text{hypotenuse}}$. For the $60^\circ$ angle, opposite side is $x$, hypotenuse is $5$.

Step2: Substitute values and solve

$\sin(60^\circ)=\frac{x}{5}$
$x=5\times\sin(60^\circ)$
$x=5\times\frac{\sqrt{3}}{2}\approx5\times0.8660$

Step3: Calculate final value

$x\approx4.33$
Round to nearest tenth: $x\approx4.3$

Answer:

$4.3$