Question

find the length of side $x$ to the nearest tenth.
(there is a right triangle with angles 30°, 60°, and 90°, one leg is 2, and the hypotenuse is $x$)
answer attempt 1 out of 2
$x = \square$ submit answer

Explanation:

Step1: Identify trigonometric ratio

We use cosine: $\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}$. For the $30^\circ$ angle, adjacent side is $x$, hypotenuse is $2$.

Step2: Substitute values into formula

$\cos(30^\circ) = \frac{x}{2}$

Step3: Solve for $x$

$x = 2 \times \cos(30^\circ) = 2 \times \frac{\sqrt{3}}{2} = \sqrt{3} \approx 1.7$

Answer:

$x = 1.7$