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Question
find the length of $overline{ac}$. use that length to find the length of $overline{cd}$. what is the length of $overline{cd}$? round to the nearest tenth. 2.3 cm 4.0 cm 10.7 cm 18.6 cm
Step1: Find length of $\overline{AC}$
In right triangle $ABC$, use $\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}$.
$\sin(30^\circ)=\frac{AC}{10}$
$AC = 10\times\sin(30^\circ)=10\times0.5=5$ cm
Step2: Find length of $\overline{CD}$
In right triangle $ACD$, use $\tan\theta=\frac{\text{opposite}}{\text{adjacent}}$.
$\tan(25^\circ)=\frac{AC}{CD}$
$CD=\frac{AC}{\tan(25^\circ)}=\frac{5}{\tan(25^\circ)}$
Calculate $\tan(25^\circ)\approx0.4663$, so $CD\approx\frac{5}{0.4663}\approx10.7$ cm
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10.7 cm (Option C)