Question

6 find the measure of each angle.
find $m\angle bac$ and $m\angle cad$.
$m\angle bac = \square^\circ$
$m\angle cad = \square^\circ$
the angles: $\angle bac=(15x - 2)^\circ$, $\angle cad=(7x + 4)^\circ$, and $\angle bad$ is a right angle

Explanation:

Step1: Set sum to 90°

$\angle BAC + \angle CAD = 90^\circ$
$(15x-2)+(7x+4)=90$

Step2: Simplify and solve for x

$22x + 2 = 90$
$22x = 88$
$x = \frac{88}{22}=4$

Step3: Calculate $\angle BAC$

Substitute $x=4$ into $15x-2$:
$15(4)-2=60-2=58$

Step4: Calculate $\angle CAD$

Substitute $x=4$ into $7x+4$:
$7(4)+4=28+4=32$

Answer:

$m\angle BAC = 58^\circ$
$m\angle CAD = 32^\circ$