Question

find the missing number so that the equation has no solutions. 3(2x - 18) + \square x + 8 = 3x - 19

Explanation:

Step1: Expand left-hand side

$3(2x - 18) + \square x + 8 = 6x - 54 + \square x + 8$

Step2: Simplify left-hand side

$(6 + \square)x - 46 = 3x - 19$

Step3: Set x coefficients equal

For no solutions, $6 + \square = 3$

Step4: Solve for the missing number

$\square = 3 - 6 = -3$
Verify constants: $-46
eq -19$, which satisfies no solutions.

Answer:

$-3$