QUESTION IMAGE
Question
find the missing side of each triangle. write your answers as decimals to the nearest hundredth.
- 10.9 in 6.5 in
- 13.5 ft 6.9 ft
find the missing side of each triangle using the pythagorean theorem. leave your answers in simplest radical form (not a decimal!)
- 8 mi 4 mi
- 6 in 4 in
use the pythagorean theorem to determine if the triangle is right, acute, or obtuse - dont go picture!
- 12 mi 15 mi 9 mi
- 9 in 5 in 13 in
- For the first right - triangle with sides 10.9 in and 6.5 in:
- # Explanation:
- ## Step1: Identify the Pythagorean Theorem
The Pythagorean Theorem for a right - triangle is \(a^{2}+b^{2}=c^{2}\), where \(c\) is the hypotenuse (the longest side) and \(a\) and \(b\) are the other two sides. Here, we assume the missing side \(x\) is the hypotenuse.
- ## Step2: Substitute the values into the formula
\(x=\sqrt{10.9^{2}+6.5^{2}}=\sqrt{118.81 + 42.25}=\sqrt{161.06}\approx12.70\) in
- # Answer:
\(x\approx12.70\) in
- For the second right - triangle with sides 13.5 ft and 6.9 ft:
- # Explanation:
- ## Step1: Use the Pythagorean Theorem
Assuming the missing side \(x\) is the hypotenuse, by the Pythagorean Theorem \(x=\sqrt{13.5^{2}+6.9^{2}}\).
- ## Step2: Calculate the values
\(x=\sqrt{182.25+47.61}=\sqrt{229.86}\approx15.16\) ft
- # Answer:
\(x\approx15.16\) ft
- For the third right - triangle with sides 4 mi and 8 mi:
- # Explanation:
- ## Step1: Apply the Pythagorean Theorem
If the missing side \(x\) is the hypotenuse, then \(x=\sqrt{4^{2}+8^{2}}\).
- ## Step2: Simplify the expression
\(x=\sqrt{16 + 64}=\sqrt{80}=4\sqrt{5}\) mi
- # Answer:
\(x = 4\sqrt{5}\) mi
- For the fourth right - triangle with sides 4 in and 6 in:
- # Explanation:
- ## Step1: Use the Pythagorean Theorem
Assuming the missing side \(x\) is the hypotenuse, \(x=\sqrt{4^{2}+6^{2}}\).
- ## Step2: Simplify the result
\(x=\sqrt{16+36}=\sqrt{52}=2\sqrt{13}\) in
- # Answer:
\(x = 2\sqrt{13}\) in
- For the fifth triangle with sides 9 mi, 12 mi, and 15 mi:
- # Explanation:
- ## Step1: Check the Pythagorean relationship
Let \(a = 9\), \(b = 12\), and \(c = 15\). Calculate \(a^{2}+b^{2}\) and \(c^{2}\). \(a^{2}+b^{2}=9^{2}+12^{2}=81 + 144=225\), and \(c^{2}=15^{2}=225\).
- ## Step2: Determine the type of triangle
Since \(a^{2}+b^{2}=c^{2}\), the triangle is a right - triangle.
- # Answer:
The triangle is a right - triangle.
- For the sixth triangle with sides 5 in, 9 in, and 13 in:
- # Explanation:
- ## Step1: Check the Pythagorean relationship
Let \(a = 5\), \(b = 9\), and \(c = 13\). Calculate \(a^{2}+b^{2}=5^{2}+9^{2}=25 + 81 = 106\), and \(c^{2}=13^{2}=169\).
- ## Step2: Determine the type of triangle
Since \(a^{2}+b^{2} The triangle is an obtuse - triangle.
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- For the first right - triangle with sides 10.9 in and 6.5 in:
- # Explanation:
- ## Step1: Identify the Pythagorean Theorem
The Pythagorean Theorem for a right - triangle is \(a^{2}+b^{2}=c^{2}\), where \(c\) is the hypotenuse (the longest side) and \(a\) and \(b\) are the other two sides. Here, we assume the missing side \(x\) is the hypotenuse.
- ## Step2: Substitute the values into the formula
\(x=\sqrt{10.9^{2}+6.5^{2}}=\sqrt{118.81 + 42.25}=\sqrt{161.06}\approx12.70\) in
- # Answer:
\(x\approx12.70\) in
- For the second right - triangle with sides 13.5 ft and 6.9 ft:
- # Explanation:
- ## Step1: Use the Pythagorean Theorem
Assuming the missing side \(x\) is the hypotenuse, by the Pythagorean Theorem \(x=\sqrt{13.5^{2}+6.9^{2}}\).
- ## Step2: Calculate the values
\(x=\sqrt{182.25+47.61}=\sqrt{229.86}\approx15.16\) ft
- # Answer:
\(x\approx15.16\) ft
- For the third right - triangle with sides 4 mi and 8 mi:
- # Explanation:
- ## Step1: Apply the Pythagorean Theorem
If the missing side \(x\) is the hypotenuse, then \(x=\sqrt{4^{2}+8^{2}}\).
- ## Step2: Simplify the expression
\(x=\sqrt{16 + 64}=\sqrt{80}=4\sqrt{5}\) mi
- # Answer:
\(x = 4\sqrt{5}\) mi
- For the fourth right - triangle with sides 4 in and 6 in:
- # Explanation:
- ## Step1: Use the Pythagorean Theorem
Assuming the missing side \(x\) is the hypotenuse, \(x=\sqrt{4^{2}+6^{2}}\).
- ## Step2: Simplify the result
\(x=\sqrt{16+36}=\sqrt{52}=2\sqrt{13}\) in
- # Answer:
\(x = 2\sqrt{13}\) in
- For the fifth triangle with sides 9 mi, 12 mi, and 15 mi:
- # Explanation:
- ## Step1: Check the Pythagorean relationship
Let \(a = 9\), \(b = 12\), and \(c = 15\). Calculate \(a^{2}+b^{2}\) and \(c^{2}\). \(a^{2}+b^{2}=9^{2}+12^{2}=81 + 144=225\), and \(c^{2}=15^{2}=225\).
- ## Step2: Determine the type of triangle
Since \(a^{2}+b^{2}=c^{2}\), the triangle is a right - triangle.
- # Answer:
The triangle is a right - triangle.
- For the sixth triangle with sides 5 in, 9 in, and 13 in:
- # Explanation:
- ## Step1: Check the Pythagorean relationship
Let \(a = 5\), \(b = 9\), and \(c = 13\). Calculate \(a^{2}+b^{2}=5^{2}+9^{2}=25 + 81 = 106\), and \(c^{2}=13^{2}=169\).
- ## Step2: Determine the type of triangle
Since \(a^{2}+b^{2} The triangle is an obtuse - triangle.