Question

find the number of protons, neutrons, and electrons in the following elements. round atomic masses to whole numbers to do these problems.

1. pr p = _, n = _, & e = _
2. v p = _, n = _, & e = _
3. b p = _, n = _, & e = _
4. mn p = _, n = _, & e = _
5. te p = _, n = _, & e = _
6. i p = _, n = _, & e = _

Explanation:

Step1: Recall atomic number and basic particle relationships

The atomic number (Z) is equal to the number of protons (p). For a neutral atom, the number of electrons (e) is equal to the number of protons. The number of neutrons (n) is calculated as mass number (A) - atomic number (Z).

Step2: Find particles for Pr (Praseodymium)

Pr has an atomic number of 59. Given mass number is considered as a whole - number for this problem. Let's assume mass number A = 141 (common isotope).
p = 59 (from atomic number)
n=A - Z = 141 - 59 = 82
e = 59 (for neutral atom)

Step3: Find particles for B (Boron)

B has an atomic number of 5. Assume mass number A = 11 (common isotope).
p = 5
n=A - Z = 11 - 5 = 6
e = 5

Step4: Find particles for Te (Tellurium)

Te has an atomic number of 52. Assume mass number A = 128 (common isotope).
p = 52
n=A - Z = 128 - 52 = 76
e = 52

Step5: Find particles for V (Vanadium)

V has an atomic number of 23. Assume mass number A = 51 (common isotope).
p = 23
n=A - Z = 51 - 23 = 28
e = 23

Step6: Find particles for Mn (Manganese)

Mn has an atomic number of 25. Assume mass number A = 55 (common isotope).
p = 25
n=A - Z = 55 - 25 = 30
e = 25

Step7: Find particles for I (Iodine)

I has an atomic number of 53. Assume mass number A = 127 (common isotope).
p = 53
n=A - Z = 127 - 53 = 74
e = 53

Answer:

1. Pr: p = 59, n = 82, e = 59
2. B: p = 5, n = 6, e = 5
3. Te: p = 52, n = 76, e = 52
4. V: p = 23, n = 28, e = 23
5. Mn: p = 25, n = 30, e = 25
6. I: p = 53, n = 74, e = 53