Question

find the percent of the total area under the standard normal curve between the following z - scores.
z = - 1.1 and z = - 0.75
click here to see page 1 of the table for areas under the standard normal curve.
click here to see page 2 of the table for areas under the standard normal curve.

the percent of the total area between z = - 1.1 and z = - 0.75 is
(round to the nearest integer.)

Explanation:

Step1: Find area for z = -1.1

Using standard - normal table, the area to the left of $z=-1.1$ is $0.1357$.

Step2: Find area for z = -0.75

Using standard - normal table, the area to the left of $z = - 0.75$ is $0.2266$.

Step3: Calculate the area between the two z - scores

The area between $z=-1.1$ and $z=-0.75$ is $0.2266 - 0.1357=0.0909$.

Step4: Convert to percentage

To convert the area to a percentage, multiply by 100: $0.0909\times100 = 9.09\%$.

Step5: Round to nearest integer

Rounding $9.09\%$ to the nearest integer gives $9\%$.

Answer:

$9$