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find the perimeter and total area of the composite shape shown below. a…

Question

find the perimeter and total area of the composite shape shown below. all measurements are given in inches. use π = 3.14 in any formulas used. options: perimeter = 52.56 inches, area = 137.12 square inches; perimeter = 46.28 inches, area = 137.12 square inches; perimeter = 65.12 inches, area = 162.24 square inches; perimeter = 52.56 inches, area = 162.24 square inches

Explanation:

Step1: Analyze the composite shape

The composite shape consists of a trapezoid and a semicircle. First, we calculate the perimeter and area separately for each part and then combine them.

Perimeter Calculation:
  • The trapezoid has two slant sides of length 10 inches each, a bottom base of 20 inches, and the top base is the diameter of the semicircle (since the radius of the semicircle is 4 inches, the diameter is \( 2\times4 = 8 \) inches). But for the perimeter, we do not include the top base of the trapezoid (where the semicircle is attached) because it is internal.
  • The semicircle's arc length is given by \( \frac{1}{2}\times2\pi r=\pi r \). With \( r = 4 \) inches and \( \pi=3.14 \), the arc length is \( 3.14\times4 = 12.56 \) inches.
  • Now, sum the lengths of the outer sides: two slant sides (10 each), the bottom base (20), and the semicircle arc (12.56).

\[
\text{Perimeter}=10 + 20+10 + 12.56=52.56 \text{ inches}
\]

Area Calculation:
  • Area of Trapezoid: The formula for the area of a trapezoid is \( \frac{(a + b)}{2}\times h \), where \( a \) and \( b \) are the two parallel sides, and \( h \) is the height. Here, \( a = 8 \) inches (top base, diameter of semicircle), \( b = 20 \) inches (bottom base), and \( h = 8 \) inches (height of trapezoid).

\[
\text{Area of Trapezoid}=\frac{(8 + 20)}{2}\times8=\frac{28}{2}\times8 = 14\times8=112 \text{ square inches}
\]

  • Area of Semicircle: The formula for the area of a full circle is \( \pi r^{2} \), so the area of a semicircle is \( \frac{1}{2}\pi r^{2} \). With \( r = 4 \) inches and \( \pi = 3.14 \):

\[
\text{Area of Semicircle}=\frac{1}{2}\times3.14\times4^{2}=\frac{1}{2}\times3.14\times16 = 3.14\times8 = 25.12 \text{ square inches}
\]

  • Total Area: Sum the area of the trapezoid and the semicircle.

\[
\text{Total Area}=112+25.12 = 137.12 \text{ square inches}
\]

Answer:

Perimeter = 52.56 inches, Area = 137.12 square inches (corresponding to the first option: Perimeter = 52.56 inches, Area = 137.12 square inches)