Question

find the product.
$(x + 3)\left(4x^{2} + 3x - 2\
ight)$
$-48x^{3} - 22x^{2} + 79x - 24$ $-56x^{3} + 9x^{2} + 99x - 56$ $-7x^{3} + 20x^{2} - 26x + 12$ $4x^{3} + 15x^{2} + 7x - 6$

Explanation:

Step1: Distribute $x$ to each term

$x \cdot 4x^2 + x \cdot 3x + x \cdot (-2) = 4x^3 + 3x^2 - 2x$

Step2: Distribute $3$ to each term

$3 \cdot 4x^2 + 3 \cdot 3x + 3 \cdot (-2) = 12x^2 + 9x - 6$

Step3: Combine like terms

$4x^3 + (3x^2 + 12x^2) + (-2x + 9x) - 6$
$= 4x^3 + 15x^2 + 7x - 6$

Answer:

D. $4x^3 + 15x^2 + 7x - 6$