Question

find the z - score that has 78.2% of the distributions area to its right.
the z - score is
(round to two decimal places as needed.)

Explanation:

Step1: Find area to the left

The total area under the standard - normal curve is 1. If the area to the right of the z - score is 0.782, then the area to the left of the z - score is $A = 1 - 0.782=0.218$.

Step2: Use the standard - normal table

We look up the value 0.218 in the body of the standard - normal (z - score) table. The closest value in the table to 0.218 gives us the z - score. Looking up 0.218 in the standard - normal table, we find that the z - score corresponding to an area of 0.218 is approximately $z=-0.78$.

Answer:

$-0.78$