Question

find the slope of each line.
1)
3)
5)

Explanation:

Problem 1:

Step1: Identify two points

Let the upper point be \((x_1, y_1)\) and lower point be \((x_2, y_2)\). From the graph, assume the grid has unit squares. Let's say the upper point is \((-1, 4)\) and lower point is \((2, -3)\) (approximate from the grid).

Step2: Use slope formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\)

\(m=\frac{-3 - 4}{2 - (-1)}=\frac{-7}{3}\)

Step1: Identify two points

The two points lie on a vertical or horizontal line? Wait, the line is horizontal? Wait, no, looking at the graph, the two points have the same \(y\)-coordinate? Wait, no, the line is vertical? Wait, no, the slope calculation: if the line is horizontal, slope is 0. Wait, the two points: let's say one is \((3, 1)\) and the other is \((3, 0)\)? No, wait, the graph shows a horizontal change? Wait, no, the line is vertical? Wait, no, the slope formula: if the line is horizontal, \(y\) doesn't change. Wait, the two points have the same \(y\)-difference? Wait, no, the line is horizontal, so \(y_2 - y_1 = 0\). So slope \(m=\frac{0}{\Delta x}=0\)

Step1: Identify two points

Let the left point be \((-3, 0)\) and right point be \((2, 1)\) (approximate from grid).

Step2: Use slope formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\)

\(m=\frac{1 - 0}{2 - (-3)}=\frac{1}{5}\) (assuming grid units, but maybe more accurate: if the rise is 1 and run is 5, slope is \(\frac{1}{5}\) or similar. Wait, maybe the points are \((-4, 0)\) and \((1, 1)\), then \(m=\frac{1 - 0}{1 - (-4)}=\frac{1}{5}\). But generally, for a shallow line, slope is positive and small. Let's assume the correct slope is \(\frac{1}{5}\) (or based on grid, if rise is 1 and run is 5, slope is \(\frac{1}{5}\)).

Answer:

\(\frac{-7}{3}\)

Problem 3: