Question

a. find the slope and y - intercept of lines ℓ and g.

Explanation:

Step1: Recall slope - intercept form

The equation of a line in slope - intercept form is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept. If we have two points $(x_1,y_1)$ and $(x_2,y_2)$ on a line, the slope $m=\frac{y_2 - y_1}{x_2 - x_1}$. To find the y - intercept, we look for the point where the line crosses the y - axis (i.e., when $x = 0$).

Step2: Assume we have points on lines $\ell$ and $g$

Let's say for line $\ell$ we have two points $(x_{1\ell},y_{1\ell})$ and $(x_{2\ell},y_{2\ell})$. Then the slope of line $\ell$, $m_{\ell}=\frac{y_{2\ell}-y_{1\ell}}{x_{2\ell}-x_{1\ell}}$. To find the y - intercept of line $\ell$, we substitute $x = 0$ into its equation or identify the y - value when $x = 0$ from its graph. Similarly for line $g$, if we have two points $(x_{1g},y_{1g})$ and $(x_{2g},y_{2g})$, the slope $m_{g}=\frac{y_{2g}-y_{1g}}{x_{2g}-x_{1g}}$, and we find its y - intercept by looking at the value of $y$ when $x = 0$.
Since no specific points or equations are given for lines $\ell$ and $g$ in the problem statement, we can't calculate numerical values. But the general process for finding the slope and y - intercept is as described above.

Answer:

For line $\ell$: slope $m_{\ell}$ is found using two points on the line with $m_{\ell}=\frac{y_{2\ell}-y_{1\ell}}{x_{2\ell}-x_{1\ell}}$, and the y - intercept is the value of $y$ when $x = 0$. For line $g$: slope $m_{g}$ is found using two points on the line with $m_{g}=\frac{y_{2g}-y_{1g}}{x_{2g}-x_{1g}}$, and the y - intercept is the value of $y$ when $x = 0$.