Question

find the slope and the y-intercept of the graph of
the linear equation.

1. $y = x + 4$ $m = $ $y$ int = 5. $y = -8x + 3$
2. $y = -\frac{5}{7}x - 2$ 7. $y = 1.75x - 1$
3. $y - 2 = 6x$ 9. $y + 7 = \frac{1}{9}x$

Explanation:

Problem 4: \( y = x + 4 \)

Step1: Recall slope - intercept form

The slope - intercept form of a linear equation is \( y=mx + b \), where \( m \) is the slope and \( b \) is the \( y \)-intercept.
For the equation \( y=x + 4 \), we can rewrite \( x \) as \( 1x \). So comparing with \( y = mx + b \), we have \( m = 1 \) and \( b=4 \).

Step1: Use slope - intercept form

The equation \( y=-8x + 3 \) is in the form \( y = mx + b \), where \( m \) is the slope and \( b \) is the \( y \)-intercept.
By comparing, we get \( m=-8 \) and \( b = 3 \).

Step1: Apply slope - intercept form

The equation \( y =-\frac{5}{7}x-2 \) is in \( y=mx + b \) form.
Here, \( m =-\frac{5}{7}\) and \( b=-2 \).

Answer:

Slope \( m = 1 \), \( y \)-intercept \(=4\)

Problem 5: \( y=-8x + 3 \)