Question

find the sum.
244 + _ = 327
_ + 143 = 281
josh has 4 binders for school. each binder can hold 4 folders. how many folders in all can josh put in his binders?
find the product.
7 × 5 = _ 12 × 6 = _
\

$$\begin{array}{r}12\\\\×3\\\\\\hline\\end{array}$$

\

$$\begin{array}{r}10\\\\×4\\\\\\hline\\end{array}$$

\

$$\begin{array}{r}4\\\\×8\\\\\\hline\\end{array}$$

use the array to write one multiplication problem and one division problem it represents.
(array of 4 rows and 5 columns of xs)
for cindy’s birthday she got 5 gifts from her parents and 6 gifts from her friends. the next day her grandmother gave her 4 more presents. if this happens every year, how many gifts will cindy receive in 6 years?
jorge’s teacher asked him to make a poster for his research project. the area of the poster must be 6 square feet. what might be the length and width of the poster?

Explanation:

Problem 1: Find the missing addend in \( 244 + \underline{\quad} = 327 \)

Step 1: Recall the addition formula

To find the missing addend, we use the formula: \( \text{Missing addend} = \text{Sum} - \text{Known addend} \)

Step 2: Substitute the values

Here, the sum is \( 327 \) and the known addend is \( 244 \). So we calculate \( 327 - 244 \)
\( 327 - 244 = 83 \)

Problem 2: Find the missing addend in \( \underline{\quad} + 143 = 281 \)

Step 1: Recall the addition formula

Using the formula \( \text{Missing addend} = \text{Sum} - \text{Known addend} \)

Step 2: Substitute the values

The sum is \( 281 \) and the known addend is \( 143 \). So we calculate \( 281 - 143 \)
\( 281 - 143 = 138 \)

Problem 3: Josh's binders and folders

Step 1: Identify the operation

Josh has \( 4 \) binders, each holding \( 4 \) folders. This is a multiplication problem: \( \text{Total folders} = \text{Number of binders} \times \text{Folders per binder} \)

Step 2: Substitute the values

Number of binders \( = 4 \), folders per binder \( = 4 \). So \( 4 \times 4 = 16 \)

Problem 4: Find the product \( 7 \times 5 \)

Answer:

s:

1. \( 244 + \boldsymbol{83} = 327 \)
2. \( \boldsymbol{138} + 143 = 281 \)
3. Josh can put \( \boldsymbol{16} \) folders in total.
4. \( 7 \times 5 = \boldsymbol{35} \) (corrected)
5. \( 12 \times 6 = \boldsymbol{72} \)
6. \( 12 \times 3 = \boldsymbol{36} \)
7. \( 10 \times 4 = \boldsymbol{40} \)
8. \( 4 \times 8 = \boldsymbol{32} \)
9. Multiplication: \( \boldsymbol{4 \times 5 = 20} \); Division: \( \boldsymbol{20 \div 4 = 5} \) (or \( 20 \div 5 = 4 \))
10. Cindy will receive \( \boldsymbol{90} \) gifts in 6 years.
11. Possible length and width: \( \boldsymbol{3} \) ft and \( \boldsymbol{2} \) ft (or \( 6 \) ft and \( 1 \) ft, etc.)