Question

1. find the sum of (8a + 2b - 4) and (3b - 5).
2. write the expression in standard form: 4(2a) + 7(-4b) + (3·c·5).

Explanation:

Problem 2:

Step1: Set up the addition

To find the sum of \((8a + 2b - 4)\) and \((3b - 5)\), we write the expression as \((8a + 2b - 4)+(3b - 5)\).

Step2: Combine like terms

First, combine the \(b\)-terms: \(2b+3b = 5b\). Then, combine the constant terms: \(-4-5=-9\). The \(a\)-term remains as \(8a\) since there is no other \(a\)-term to combine with. So the sum is \(8a + 5b-9\).

Step1: Simplify each term

• For the first term \(4(2a)\), multiply \(4\) and \(2\) to get \(8a\).
• For the second term \(7(-4b)\), multiply \(7\) and \(-4\) to get \(-28b\).
• For the third term \((3\cdot c\cdot5)\), multiply \(3\) and \(5\) to get \(15c\).

Step2: Write in standard form

Combine the simplified terms: \(8a-28b + 15c\).

Answer:

\(8a + 5b - 9\)

Problem 3: