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find the value of ∠a. your answer could be a decimal. ∠a = 6x + 9 ∠b = …

Question

find the value of ∠a. your answer could be a decimal. ∠a = 6x + 9 ∠b = 4x - 1

Explanation:

Step1: Identify angle - relationship

Since the two lines are parallel, $\angle A$ and $\angle B$ are corresponding angles and are equal. So, $6x + 9=4x - 1$.

Step2: Solve the equation for $x$

Subtract $4x$ from both sides: $6x-4x + 9=4x-4x - 1$, which simplifies to $2x+9=-1$. Then subtract 9 from both sides: $2x+9 - 9=-1 - 9$, getting $2x=-10$. Divide both sides by 2: $x=\frac{-10}{2}=-5$.

Step3: Find the value of $\angle A$

Substitute $x = - 5$ into the expression for $\angle A$. $\angle A=6x + 9=6\times(-5)+9=-30 + 9=-21$. But angles cannot be negative in this context. There was a wrong - assumption. $\angle A$ and $\angle B$ are same - side interior angles, so $\angle A+\angle B = 180^{\circ}$.

Step4: Set up the correct equation

$(6x + 9)+(4x - 1)=180$. Combine like - terms: $6x+4x+9 - 1=180$, which gives $10x+8 = 180$.

Step5: Solve the new equation for $x$

Subtract 8 from both sides: $10x+8 - 8=180 - 8$, so $10x=172$. Divide both sides by 10: $x = 17.2$.

Step6: Calculate $\angle A$

Substitute $x = 17.2$ into the expression for $\angle A$. $\angle A=6x + 9=6\times17.2+9=103.2+9=112.2$.

Answer:

$112.2$