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find the value of x. the right triangle has sides 1.8mi and 0.8mi, with…

Question

find the value of x. the right triangle has sides 1.8mi and 0.8mi, with x being the side on the straight line corresponding to the hypotenuse of the right triangle.a $sqrt{3.88} approx 1.97$ milesb $sqrt{2.6} approx 1.61$ milesc $sqrt{3.24} approx 1.8$ milesd $sqrt{0.16} approx 0.4$ miles

Explanation:

Step1: Identify theorem to use

This is a right triangle, so apply the Pythagorean theorem: for right triangle with hypotenuse $c$ and legs $a,b$, $c^2=a^2+b^2$. Here, $x$ is the hypotenuse, $a=1.8$, $b=0.8$.

Step2: Calculate $x^2$

$$x^2 = 1.8^2 + 0.8^2$$
$$x^2 = 3.24 + 0.64 = 3.88$$

Step3: Solve for $x$

$$x = \sqrt{3.88} \approx 1.97$$

Answer:

A. $\sqrt{3.88} \approx 1.97$ miles