Question

find the values of x and y that satisfy the equation.\\(-10x + 12i = 20 + 3yi\\)\\(x = \square\\) and \\(y = \square\\)

Explanation:

Step1: Equate real parts

$-10x = 20$

Step2: Solve for x

$x = \frac{20}{-10} = -2$

Step3: Equate imaginary parts

$12 = 3y$

Step4: Solve for y

$y = \frac{12}{3} = 4$

Answer:

$x = -2$ and $y = 4$