Question

find the vertex.
f(x) = 3x² - 6x + 2
(?, )

Explanation:

Step1: Find x-coordinate of vertex

For quadratic $ax^2+bx+c$, $x=-\frac{b}{2a}$.
Here $a=3$, $b=-6$, so:
$x=-\frac{-6}{2\times3}=\frac{6}{6}=1$

Step2: Find y-coordinate of vertex

Substitute $x=1$ into $f(x)$:
$f(1)=3(1)^2-6(1)+2=3-6+2=-1$

Answer:

$(1, -1)$