Question

find wx.
write your answer in simplified, rationalized form. do not round.
wx =

Explanation:

Step1: Identify adjacent side, hypotenuse

In right $\triangle WXV$, $\angle W=60^\circ$, hypotenuse $WV=36\sqrt{11}$, $WX$ is adjacent to $\angle W$.

Step2: Use cosine definition

$\cos(\theta)=\frac{\text{adjacent}}{\text{hypotenuse}}$, so $\cos(60^\circ)=\frac{WX}{36\sqrt{11}}$.

Step3: Substitute $\cos(60^\circ)=\frac{1}{2}$

$\frac{1}{2}=\frac{WX}{36\sqrt{11}}$

Step4: Solve for $WX$

$WX = \frac{1}{2} \times 36\sqrt{11} = 18\sqrt{11}$

Answer:

$18\sqrt{11}$