QUESTION IMAGE
Question
- ∠fmg and ∠hmk are straight angles 1. given
- m∠fmg = 180° and m∠hmk = 180° 2. definition of straight angle
- m∠fmk + m∠kmg = m∠fmg m∠hmf + m∠fmk = m∠hmk 3. angle addition postulate
- 4. substitution property of equality
- m∠fmk + m∠kmg = m∠hmf + m∠fmk 5. transitive property of equality
- m∠fmk = m∠fmk 6. reflexive property of equality
- 7. subtraction property of equality
Step1: Substitute values from step 2 into step 3
Since \(m\angle FMG = 180^{\circ}\) and \(m\angle HMK=180^{\circ}\), we get \(m\angle FMK + m\angle KMG=180^{\circ}\) and \(m\angle HMF + m\angle FMK = 180^{\circ}\)
Step2: Use subtraction property of equality
Subtract \(m\angle FMK\) from both sides of the equation \(m\angle FMK + m\angle KMG=m\angle HMF + m\angle FMK\). We get \(m\angle KMG=m\angle HMF\)
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\(m\angle KMG=m\angle HMF\)