Question

the following chemical reaction takes place in aqueous solution: agf(aq)+nabr(aq)→agbr(s)+naf(aq) write the net ionic equation for this reaction.

Explanation:

Step1: Write the complete ionic equation

In aqueous solution, soluble ionic compounds dissociate into ions. AgF(aq) dissociates into Ag⁺(aq) and F⁻(aq), NaBr(aq) dissociates into Na⁺(aq) and Br⁻(aq), AgBr(s) does not dissociate as it is a solid - precipitate, and NaF(aq) dissociates into Na⁺(aq) and F⁻(aq). So the complete ionic equation is: Ag⁺(aq)+F⁻(aq)+Na⁺(aq)+Br⁻(aq)→AgBr(s)+Na⁺(aq)+F⁻(aq)

Step2: Identify and cancel out the spectator ions

Spectator ions are ions that appear on both sides of the equation and do not participate in the actual reaction. Here, Na⁺(aq) and F⁻(aq) are spectator ions.

Step3: Write the net - ionic equation

After canceling out the spectator ions, the net - ionic equation is: Ag⁺(aq)+Br⁻(aq)→AgBr(s)

Answer:

Ag⁺(aq)+Br⁻(aq)→AgBr(s)