Question

the following table shows a certain countrys petrochemical exports to another country (in billions of dollars) for several years. let $x = 10$ correspond to the year 2010. two equations that model these data are $y = 1.18x + 2.23$ and $y = 2x - 4$. complete parts (a) through (c) below.

year 2010 2011 2012 2013 2014
petrochemical exports 15 17 18 19 21.4

(type an integer or a decimal.)
find the residuals for the second model, $y = 2x - 4$.

year 2010 2011 2012 2013 2014
residual -1 -1 -2 -3 -2.6
(type integers or decimals.)
the sum of the residuals for $y = 2x - 4$ is -9.6
(type an integer or a decimal.)
(b) find the sum of the squares of the residuals for each model.
the sum of the squares of the residuals for $y = 1.18x + 2.23$ is 15.80
(round the final answer to two decimal places as needed. round all intermediate values to two decimal places as needed.)
the sum of the squares of the residuals for $y = 2x - 4$ is
(round the final answer to two decimal places as needed. round all intermediate values to two decimal places as needed.)

Explanation:

Step1: List residuals for y=2x-4

Residuals: $-1, -1, -2, -3, -2.6$

Step2: Square each residual

$(-1)^2=1$, $(-1)^2=1$, $(-2)^2=4$, $(-3)^2=9$, $(-2.6)^2=6.76$

Step3: Sum the squared residuals

$1 + 1 + 4 + 9 + 6.76 = 21.76$

Answer:

21.76