Question

form the operation.
$(2x^2 - 3x + 1) + (7x^2 + 10x + 8)$

Explanation:

Step1: Remove parentheses

We have \((2x^2 - 3x + 1)+(7x^2 + 10x + 8)\). Removing the parentheses (since there's a plus sign in front of both, the signs inside stay the same), we get \(2x^2 - 3x + 1 + 7x^2 + 10x + 8\).

Step2: Combine like terms for \(x^2\) terms

The \(x^2\) terms are \(2x^2\) and \(7x^2\). Combining them: \(2x^2+7x^2 = 9x^2\).

Step3: Combine like terms for \(x\) terms

The \(x\) terms are \(-3x\) and \(10x\). Combining them: \(-3x + 10x=7x\).

Step4: Combine constant terms

The constant terms are \(1\) and \(8\). Combining them: \(1 + 8 = 9\).

Step5: Write the final expression

Putting the combined terms together, we have \(9x^2+7x + 9\).

Answer:

\(9x^2 + 7x + 9\)