Question

a formula for determining the rate of increase in size for a geometric area in two - dimensional space when the rate is constant can be calculated by subtracting the original area from the new area and dividing by elapsed time, such that: $\frac{a_1 - a_0}{t}$ or $(a_1 - a_0)div t$. for a square geometric area with $a = s^2$, the formula could be rewritten as follows, where lower case s equals a side of a square. $\frac{s_1^2 - s_0^2}{t}$. solve for a geometric square in rate of expansion in square units per second with a side of 5 units at start, or $s_0$, and 13 units after expanding, or $s_1$, over 12 seconds. (you do not need to include the units. only enter the number value for an answer. round to the nearest hundredth if necessary.)

Explanation:

Step1: Identify values

$s_0 = 5$, $s_1=13$, $t = 12$

Step2: Substitute values into formula

$\frac{s_1^{2}-s_0^{2}}{t}=\frac{13^{2}-5^{2}}{12}$

Step3: Calculate numerator

$13^{2}-5^{2}=169 - 25=144$

Step4: Calculate final result

$\frac{144}{12}=12$

Answer:

12