Question

formula 6 points. how much j of heat is required to increase the temperature of 8.24 kg of iron from 25.00 °c to 225 °c? the specific heat capacity of iron is 0.451 j/g°c. solve to 3 significant figures.

Explanation:

Step1: Identify the formula

The formula for heat $Q = mc\Delta T$, where $m$ is the mass, $c$ is the specific - heat capacity, and $\Delta T$ is the change in temperature.

Step2: Calculate the change in temperature

$\Delta T=T_2 - T_1=225^{\circ}C - 25.00^{\circ}C = 200^{\circ}C$.

Step3: Substitute the values into the formula

$m = 8.24$ kg, $c=0.451$ J/g°C. First, convert the mass to grams: $m = 8.24\times1000 = 8240$ g. Then $Q=mc\Delta T=(8240\text{ g})\times(0.451\text{ J/g°C})\times(200^{\circ}C)$.

Step4: Perform the calculation

$Q = 8240\times0.451\times200\text{ J}=8240\times90.2\text{ J}=743248\text{ J}\approx743000\text{ J}$ (to 3 significant figures).

Answer:

$743000$ J