Question

the four blades in a four - piece chisel set contain cutting - edge widths of $\frac{1}{5}$ in, $\frac{1}{4}$ in, $\frac{5}{7}$ in, and 1 in. find the difference in the cutting - edge width of the two chisels with the widest blades. the difference in the cutting - edge width of the two chisels with the widest blades is $square$ in. (type a whole number or a simplified fraction.)

Explanation:

Step1: Identify the two widest blades

First, we compare the given fractions and the whole number. The widths are $\frac{1}{5}$, $\frac{1}{4}$, $\frac{5}{7}$, and $1$. We know that $1$ is a whole number, and to compare the fractions, we can find a common denominator or convert them to decimals.

• $\frac{1}{5} = 0.2$
• $\frac{1}{4} = 0.25$
• $\frac{5}{7} \approx 0.714$
• $1 = 1$

So the two widest blades have widths $1$ in and $\frac{5}{7}$ in.

Step2: Calculate the difference

To find the difference between $1$ and $\frac{5}{7}$, we subtract: $1 - \frac{5}{7}$. We can write $1$ as $\frac{7}{7}$, so $\frac{7}{7} - \frac{5}{7} = \frac{7 - 5}{7} = \frac{2}{7}$.

Answer:

$\frac{2}{7}$