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the four compounds below have similar molar masses. rank the pure liqui…

Question

the four compounds below have similar molar masses. rank the pure liquids of the four compounds in order of increasing boiling point (i.e. 1 = lowest boiling point and 4 = highest boiling point). 1 c(ch3)4 2 ch3ch2och2ch3 4 ch3ch2ch2ch2oh 3 ch3ch2ch2ch2ch3

Explanation:

Step1: Analyze intermolecular forces

Intermolecular forces affect boiling - point. The stronger the intermolecular forces, the higher the boiling - point.

Step2: Identify forces in $C(CH_3)_4$

$C(CH_3)_4$ (neopentane) is a non - polar molecule. It has only London dispersion forces.

Step3: Identify forces in $CH_3CH_2OCH_2CH_3$

$CH_3CH_2OCH_2CH_3$ (diethyl ether) is a polar molecule due to the presence of the oxygen atom. It has dipole - dipole forces in addition to London dispersion forces.

Step4: Identify forces in $CH_3CH_2CH_2CH_2OH$

$CH_3CH_2CH_2CH_2OH$ (1 - butanol) has hydrogen bonding (due to the $-OH$ group), in addition to dipole - dipole and London dispersion forces. Hydrogen bonding is a very strong intermolecular force.

Step5: Identify forces in $CH_3CH_2CH_2CH_2CH_3$

$CH_3CH_2CH_2CH_2CH_3$ (pentane) is a non - polar molecule and has only London dispersion forces. But its surface area is larger than that of $C(CH_3)_4$, so it has stronger London dispersion forces.

Since London dispersion forces are weaker than dipole - dipole forces, and hydrogen bonding is the strongest among these intermolecular forces:

  1. $C(CH_3)_4$ has the weakest intermolecular forces (only London dispersion forces and relatively small surface area), so it has the lowest boiling - point (rank 1).
  2. $CH_3CH_2OCH_2CH_3$ has dipole - dipole and London dispersion forces, so it has a higher boiling - point than $C(CH_3)_4$ (rank 2).
  3. $CH_3CH_2CH_2CH_2CH_3$ has stronger London dispersion forces than $C(CH_3)_4$ due to its larger surface area, so it has a higher boiling - point than $CH_3CH_2OCH_2CH_3$ (rank 3).
  4. $CH_3CH_2CH_2CH_2OH$ has hydrogen bonding, so it has the highest boiling - point (rank 4).

Answer:

  1. $C(CH_3)_4$
  2. $CH_3CH_2OCH_2CH_3$
  3. $CH_3CH_2CH_2CH_2CH_3$
  4. $CH_3CH_2CH_2CH_2OH$