Question

four different objects are placed on a number line at 0. the chart describes the motion of each object.

object | motion
--- | ---
w | 3 units left, then 3 units right
x | 6 units right, then 18 units right
y | 8 units left, then 24 units right
z | 16 units right, then 8 units left

using the information in the chart, the distance and displacement of each object can be determined. which object has a distance that is three times as great as its displacement?
w
x
y
z

Explanation:

Step1: Define right as positive, left as negative.

Let right = $+$, left = $-$

Step2: Calculate Object W: distance & displacement

Distance: $|3| + |3| = 6$
Displacement: $-3 + 3 = 0$

Step3: Calculate Object X: distance & displacement

Distance: $|6| + |18| = 24$
Displacement: $6 + 18 = 24$

Step4: Calculate Object Y: distance & displacement

Distance: $|8| + |24| = 32$
Displacement: $-8 + 24 = 16$

Step5: Calculate Object Z: distance & displacement

Distance: $|16| + |8| = 24$
Displacement: $16 - 8 = 8$

Step6: Check 3× displacement = distance

For Z: $3 \times 8 = 24$, which matches distance.

Answer:

Z