Question

is the function $f(x)=x^4 + x$ even?
use the drop - down menus to complete the statements.
click the arrows to choose an answer from each menu.
to determine if $f(x)$ is even, find $f(-x) =$ choose... . because $f(-x)$ choose... equal to $f(x)$, the function choose... even.

Explanation:

Step1: Compute $f(-x)$

Substitute $x$ with $-x$ in $f(x)$:
$f(-x) = (-x)^4 + (-x) = x^4 - x$

Step2: Compare $f(-x)$ and $f(x)$

$f(x) = x^4 + x$, so $f(-x) = x^4 - x
eq f(x)$

Step3: Classify the function

Since $f(-x)
eq f(x)$, the function is not even.

Answer:

To determine if $f(x)$ is even, find $f(-x) = \boldsymbol{x^4 - x}$. Because $f(-x)$ $\boldsymbol{is\ not}$ equal to $f(x)$, the function $\boldsymbol{is\ not}$ even.