Question

the functions r and s are defined as follows.
$r(x)=2x-1$
$s(x)=-2x^2 + 1$
find the value of $s(r(3))$.
$s(r(3))=\square$

Explanation:

Step1: Calculate r(3)

Substitute $x=3$ into $r(x)$:
$r(3)=2(3)-1=6-1=5$

Step2: Calculate s(r(3))

Substitute $x=5$ into $s(x)$:
$s(5)=-2(5)^2 +1=-2(25)+1=-50+1$

Answer:

$-49$