Question

gas laws practice

1. a gas in a sealed container has a starting pressure of 100kpa and a volume of 6l. if the volume of the container is increased to 12l, what would the new pressure be?

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1. a gas in a sealed container has a starting pressure of 100kpa and a temperature of 30°c. if the temperature is raised to 60°c what is the new pressure? (remember that you need to do this in kelvin: k = °c + 273)

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1. a gas in a sealed container has a starting volume of 4l and a temperature of 100°c. if the temperature is lowered to 50°c, what is the new volume of the container? (remember that you need to do this in kelvin: k = °c + 273)

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1. a gas in a sealed container has a starting pressure of 100kpa and a volume of 6l. if the pressure is increased to 150kpa, what would the new volume be?

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Explanation:

Step1: Identify the gas - law formula for the first problem

For a gas at constant temperature (Boyle's law), $P_1V_1 = P_2V_2$. Given $P_1 = 100$ kPa, $V_1=6$ L, and $V_2 = 12$ L.
$P_2=\frac{P_1V_1}{V_2}$

Step2: Calculate the new pressure

$P_2=\frac{100\times6}{12}=50$ kPa

Step3: Identify the gas - law formula for the second problem

For a gas at constant volume (Gay - Lussac's law), $\frac{P_1}{T_1}=\frac{P_2}{T_2}$. First, convert temperatures to Kelvin. $T_1=30 + 273=303$ K, $T_2=60 + 273 = 333$ K, and $P_1 = 100$ kPa. Then $P_2=\frac{P_1T_2}{T_1}$.
$P_2=\frac{100\times333}{303}\approx110$ kPa

Step4: Identify the gas - law formula for the third problem

For a gas at constant pressure (Charles's law), $\frac{V_1}{T_1}=\frac{V_2}{T_2}$. Convert temperatures to Kelvin. $T_1=100 + 273=373$ K, $T_2=50+273 = 323$ K, and $V_1 = 4$ L. Then $V_2=\frac{V_1T_2}{T_1}$.
$V_2=\frac{4\times323}{373}\approx3.46$ L

Step5: Identify the gas - law formula for the fourth problem

For a gas at constant temperature (Boyle's law), $P_1V_1 = P_2V_2$. Given $P_1 = 100$ kPa, $V_1=6$ L, and $P_2 = 150$ kPa. Then $V_2=\frac{P_1V_1}{P_2}$.
$V_2=\frac{100\times6}{150}=4$ L

Answer:

1. 50 kPa
2. Approximately 110 kPa
3. Approximately 3.46 L
4. 4 L