Question

a gas occupies a volume of 6.0 l at a pressure of 2.0 atm. if the gas is compressed to a volume of 3,000 ml, what will be the new pressure of the gas, assuming the temperature remains constant? a .004 atm b 4 atm c 9,000 atm d 9.0 atm

Explanation:

Step1: Convert volume units

First, convert 3000 mL to liters. Since 1 L = 1000 mL, so \( 3000\space mL=\frac{3000}{1000} = 3.0\space L\).

Step2: Apply Boyle's Law

Boyle's Law states that \( P_1V_1 = P_2V_2\) (at constant temperature), where \( P_1 = 2.0\space atm\), \( V_1 = 6.0\space L\), \( V_2 = 3.0\space L\), and we need to find \( P_2\).
Rearranging the formula for \( P_2\), we get \( P_2=\frac{P_1V_1}{V_2}\).
Substitute the values: \( P_2=\frac{2.0\space atm\times6.0\space L}{3.0\space L}\).

Step3: Calculate the new pressure

Simplify the expression: \( \frac{2.0\times6.0}{3.0}=\frac{12.0}{3.0} = 4.0\space atm\).

Answer:

B. 4 atm