Question

give the complete electron configuration for the sulfur ion in problem 6. do not use the noble gas abbreviation. the s ion has 1 electrons 1s² 2s² 2p⁶ 2 3 a. 10 b. 12 c. 14 d. 16 e. 18 f. 36 g. 38 h. 39 i. 40 j. 3p⁶ k. 3p⁴ l. 3s² m. 3d¹⁰ n. 4d¹ o. 4s² p. 4p⁶ q. 5s² r. 5s⁰ s. 4d⁰ t. 4d³ u. 5s¹ v. 3p⁵

Explanation:

Step1: Determine sulfur ion electrons

Sulfur (S) has an atomic number of 16. Sulfur commonly forms a - 2 ion ($S^{2 -}$), so it has 16 + 2=18 electrons.

Step2: Write electron - configuration order

Electrons fill orbitals in the order 1s, 2s, 2p, 3s, 3p. After $1s^{2}2s^{2}2p^{6}$, the next orbitals to fill are 3s and 3p. The 3s orbital can hold 2 electrons and the 3p orbital can hold 6 electrons.

Answer:

1. E. 18
2. L. $3s^{2}$
3. J. $3p^{6}$