Question

give the complete electron configuration for the yttrium ion in problem 9. do not use the noble gas abbreviation. the y ion has 1 electrons 1s² 2s² 2p⁶ 3s² 3p⁶ 2 3 4 5 6 a. 10 b. 12 c. 14 d. 16 e. 18 f. 36 g. 38 h. 39 i. 40 j. 3p⁶ k. 3p⁴ l. 3s² m. 3d¹⁰ n. 4d¹ o. 4s² p. 4p⁶ q. 5s² r. 5s⁰ s. 4d⁰ t. 4d³ u. 5s¹ v. 3p⁵

Explanation:

Step1: Determine atomic number of yttrium

Yttrium (Y) has an atomic number of 39, which means a neutral Y atom has 39 electrons.

Step2: Consider common yttrium ion charge

Yttrium commonly forms a +3 ion ($Y^{3 +}$). When it forms a +3 ion, it loses 3 electrons. So the number of electrons in $Y^{3+}$ is $39 - 3=36$.

Step3: Write electron - configuration

The electron - configuration of an atom/ion with 36 electrons follows the Aufbau principle. After $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}$, the next orbitals are filled as $4s^{2}3d^{10}4p^{6}$.

Answer:

1. F. 36
2. O. $4s^{2}$
3. M. $3d^{10}$
4. P. $4p^{6}$
5. R. $5s^{0}$
6. S. $4d^{0}$