Question

give the noble gas abbreviated electron configuration for the two thallium ions using the orbital (box) method. use oxidation numbers from the periodic table. one ion completely empties the 6s subshell, use 6s^0 to hold its place. the tl+1 ion has 1 electrons and 2 core electrons. 3 64 45 56 67

Explanation:

Step1: Determine atomic number of thallium

Thallium (Tl) has an atomic number of 81. A neutral Tl atom has 81 electrons. The $Tl^{+1}$ ion is formed by losing 1 electron. So, the number of electrons in $Tl^{+1}$ is $81 - 1=80$.

Step2: Identify core - electrons

The noble - gas core of thallium is [Xe]. Xenon (Xe) has an atomic number of 54. So, the number of core - electrons in $Tl^{+1}$ is 54.

Step3: Write noble - gas abbreviated electron configuration

The noble - gas core is [Xe]. After the noble - gas core, the electron configuration starts with the next energy levels. The electron configuration of $Tl^{+1}$ is $[Xe]4f^{14}5d^{10}6s^{0}6p^{2}$.

Answer:

1. 80
2. 54
3. Xe
4. $s^{0}$
5. $f^{14}$
6. $d^{10}$
7. $p^{2}$