Question

give the number of protons and electrons in each of the following common ions: ions protons electrons al³⁺ h⁺ i⁻

Explanation:

Step1: Recall atomic number for Al

The atomic number of aluminum (Al) is 13. Protons number equals atomic number for an element. So for $Al^{3 +}$, number of protons = 13.

Step2: Calculate electrons for $Al^{3 +}$

A $Al^{3 +}$ ion has lost 3 electrons. So number of electrons = 13 - 3=10.

Step3: Recall atomic number for H

The atomic number of hydrogen (H) is 1. So for $H^{+}$, number of protons = 1.

Step4: Calculate electrons for $H^{+}$

A $H^{+}$ ion has lost 1 electron. So number of electrons = 1 - 1 = 0.

Step5: Recall atomic number for I

The atomic number of iodine (I) is 53. So for $I^{-}$, number of protons = 53.

Step6: Calculate electrons for $I^{-}$

An $I^{-}$ ion has gained 1 electron. So number of electrons = 53+ 1 = 54.

Answer:

ions	protons	electrons
$H^{+}$	1	0
$I^{-}$	53	54