QUESTION IMAGE
Question
give the percent increase or percent decrease for each equation.
- $y = 50(2)^x$
- $y = 1.25(0.95)^x$
- $y = 0.9(0.8)^x$
- $y = 3(3.4)^x$
- $y = 10(0.855)^x$
- $y = 30(10)^x$
- $y = 0.5(1.23)^x$
- $y = 1.3(0.005)^x$
- $y = 2(1.3)^x$
- $y = 1.5(0.45)^x$
- $y = 0.5(0.3)^x$
- $y = 1.3(4.075)^x$
Step1: Recall exponential form rule
Exponential growth/decay form: $y = a(b)^x$, where $b = 1 + r$ (growth, $r>0$) or $b = 1 - r$ (decay, $r<0$). $r$ is decimal rate, convert to % by $\times100$.
Step2: Solve #19: $y=50(2)^x$
$b=2=1+r \implies r=2-1=1$. Percent increase: $1\times100=100\%$
Step3: Solve #21: $y=1.25(0.95)^x$
$b=0.95=1-r \implies r=1-0.95=0.05$. Percent decrease: $0.05\times100=5\%$
Step4: Solve #22: $y=0.9(0.8)^x$
$b=0.8=1-r \implies r=1-0.8=0.2$. Percent decrease: $0.2\times100=20\%$
Step5: Solve #23: $y=3(3.4)^x$
$b=3.4=1+r \implies r=3.4-1=2.4$. Percent increase: $2.4\times100=240\%$
Step6: Solve #24: $y=10(0.855)^x$
$b=0.855=1-r \implies r=1-0.855=0.145$. Percent decrease: $0.145\times100=14.5\%$
Step7: Solve #25: $y=30(10)^x$
$b=10=1+r \implies r=10-1=9$. Percent increase: $9\times100=900\%$
Step8: Solve #26: $y=0.5(1.23)^x$
$b=1.23=1+r \implies r=1.23-1=0.23$. Percent increase: $0.23\times100=23\%$
Step9: Solve #27: $y=1.3(0.005)^x$
$b=0.005=1-r \implies r=1-0.005=0.995$. Percent decrease: $0.995\times100=99.5\%$
Step10: Solve #28: $y=2(1.3)^x$
$b=1.3=1+r \implies r=1.3-1=0.3$. Percent increase: $0.3\times100=30\%$
Step11: Solve #29: $y=1.5(0.45)^x$
$b=0.45=1-r \implies r=1-0.45=0.55$. Percent decrease: $0.55\times100=55\%$
Step12: Solve #30: $y=0.5(0.3)^x$
$b=0.3=1-r \implies r=1-0.3=0.7$. Percent decrease: $0.7\times100=70\%$
Step13: Solve #31: $y=1.3(4.075)^x$
$b=4.075=1+r \implies r=4.075-1=3.075$. Percent increase: $3.075\times100=307.5\%$
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