QUESTION IMAGE
Question
- given: 2pq = pr
prove: q is the mid - point of (overline{pr})
| statements | reasons |
|---|---|
| 2. | 2. segment addition postulate |
| 3. 2pq = pq + qr | 3. |
| 4. pq = qr | 4. |
| 5. | 5. definition of midpoint |
Step1: State the given
$2PQ = PR$
Step2: Apply segment - addition postulate
$PR=PQ + QR$
Step3: Substitute $PR$
Since $2PQ = PR$ and $PR = PQ+QR$, we have $2PQ=PQ + QR$
Step4: Subtract $PQ$ from both sides
$2PQ - PQ=PQ + QR - PQ$, so $PQ = QR$
Step5: Use mid - point definition
Since $PQ = QR$, $Q$ is the mid - point of $\overline{PR}$
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- $2PQ = PR$; Given
- $PR=PQ + QR$; Segment Addition Postulate
- $2PQ=PQ + QR$; Substitution (using 1 and 2)
- $PQ = QR$; Subtraction Property of Equality (subtracted $PQ$ from both sides of 3)
- $Q$ is the mid - point of $\overline{PR}$; Definition of Midpoint