QUESTION IMAGE
Question
- given ( f(x) = x^2 - 4x + 7 )
a. find the average rate of change of the function on the interval (-1,1).
b. describe the relationship between the rate of change and the behavior of the function on this interval.
c. how would you describe the rate of change at ( x = 2 )?
Part A
Step1: Recall the average rate of change formula
The average rate of change of a function \( f(x) \) on the interval \([a, b]\) is given by \(\frac{f(b)-f(a)}{b - a}\). Here, \( a=-1 \) and \( b = 1 \), and \( f(x)=x^{2}-4x + 7 \).
Step2: Calculate \( f(-1) \)
Substitute \( x=-1 \) into \( f(x) \):
\[
\]
Step3: Calculate \( f(1) \)
Substitute \( x = 1 \) into \( f(x) \):
\[
\]
Step4: Calculate the average rate of change
Using the formula \(\frac{f(1)-f(-1)}{1-(-1)}\):
\[
\]
The average rate of change we found is \(-4\) (negative). For a quadratic function \( f(x)=x^{2}-4x + 7 \), the graph is a parabola opening upwards (since the coefficient of \( x^{2} \) is positive). The vertex of the parabola \( y = ax^{2}+bx + c \) is at \( x=-\frac{b}{2a}\), here \( x =-\frac{-4}{2\times1}=2 \). On the interval \([-1,1]\), which is to the left of the vertex \( x = 2 \), the function is decreasing (because as \( x \) increases from \(-1\) to \( 1 \), the \( y \)-values decrease from \( 12 \) to \( 4 \)). A negative average rate of change indicates that the function is decreasing on the interval \([-1,1]\), so the rate of change (negative) is consistent with the function's behavior of decreasing on this interval.
Step1: Recall the concept of instantaneous rate of change
The rate of change at a point \( x = a \) for a function \( f(x) \) is the instantaneous rate of change, which is given by the derivative of the function at \( x = a \), i.e., \( f^{\prime}(a) \).
Step2: Find the derivative of \( f(x) \)
Given \( f(x)=x^{2}-4x + 7 \), using the power rule \((x^{n})^\prime=nx^{n - 1}\), the derivative \( f^{\prime}(x) \) is:
\[
f^{\prime}(x)=2x-4
\]
Step3: Evaluate the derivative at \( x = 2 \)
Substitute \( x = 2 \) into \( f^{\prime}(x) \):
\[
f^{\prime}(2)=2(2)-4=4 - 4=0
\]
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The average rate of change on \([-1,1]\) is \(-4\).