Question

(a) given ( f(x) = 6x^2 + 2|x| ), find ( f(-x) ).
( f(-x) = 6(-x)^2 + 2|(-x)| )
( = \boxed{6x^2 + 2|x|} )
part 2 of 3
(b) is ( f(-x) = f(x) )?
select

Explanation:

Step1: Recall $f(-x)$ result

From part (a), $f(-x)=6x^2+2|x|$

Step2: Compare to $f(x)$

Given $f(x)=6x^2+2|x|$, so $f(-x)=f(x)$

Answer:

Yes, $f(-x)=f(x)$