QUESTION IMAGE
Question
given: abcd is a parallelogram
prove: ∠abc≅∠cda
statement: reason:
abcd is a parallelogram
- a. opposite angles of a parallelogram are congruent b. cpctc c. definition of parallelogram d. given
ba∥dc
- a. definition of parallelogram (opposite sides are parallel) b. alternate interior angles c. opposite sides of a parallelogram are congruent d. reflexive property
- alternate interior angles a. ∠adc≅∠dac b. ∠bac≅∠dca c. ∠cab≅∠dac d. ∠bca≅∠dca
- opposite sides of a parallelogram are congruent a. ab≅ab b. ab≅dc c. ab≅ac d. ab≅ad
ac≅ac
- a. reflexive property b. diagonals bisect each other c. transitive property d. symmetric property
∠abc≅∠cda
- a. aas b. sas c. hl d. asa
∠abc≅∠cda
- a. alternate interior angles b. vertical angles c. definition of parallelogram d. cpctc
Step1: Identify the reason for the given statement
The statement "ABCD is a parallelogram" is given in the problem - set up. So the reason is "Given".
Step2: Reason for $\overline{BA}\parallel\overline{DC}$
By the definition of a parallelogram, opposite sides are parallel. So $\overline{BA}\parallel\overline{DC}$ because of the definition of a parallelogram.
Step3: Find the alternate - interior angles
Since $\overline{BA}\parallel\overline{DC}$ and $\overline{AC}$ is a transversal, $\angle BAC\cong\angle DCA$ by the alternate - interior angles theorem.
Step4: Identify congruent sides of the parallelogram
Opposite sides of a parallelogram are congruent. So $\overline{AB}\cong\overline{DC}$.
Step5: Reason for $\overline{AC}\cong\overline{AC}$
The side $\overline{AC}$ is common to both $\triangle ABC$ and $\triangle CDA$. By the reflexive property, $\overline{AC}\cong\overline{AC}$.
Step6: Prove the triangles congruent
In $\triangle ABC$ and $\triangle CDA$, we have $\angle BAC\cong\angle DCA$, $\overline{AB}\cong\overline{DC}$, and $\overline{AC}\cong\overline{AC}$. So $\triangle ABC\cong\triangle CDA$ by the SAS (Side - Angle - Side) congruence criterion.
Step7: Prove the angles congruent
Since $\triangle ABC\cong\triangle CDA$, then $\angle ABC\cong\angle CDA$ by CPCTC (Corresponding Parts of Congruent Triangles are Congruent).
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- D. Given
- A. Definition of parallelogram (Opposite sides are parallel)
- B. $\angle BAC\cong\angle DCA$
- B. $\overline{AB}\cong\overline{DC}$
- A. Reflexive property
- B. SAS
- D. CPCTC