Question

given bd=9.4 and ce=19, find the area of rhombus bcde. round your answer to the nearest tenth if necessary.

Explanation:

Step1: Recall the formula for the area of a rhombus

The area \( A \) of a rhombus is given by the formula \( A=\frac{1}{2}d_1d_2 \), where \( d_1 \) and \( d_2 \) are the lengths of the diagonals.

Step2: Identify the diagonals

Here, \( d_1 = BD = 9.4 \) and \( d_2=CE = 19 \).

Step3: Substitute the values into the formula

Substitute \( d_1 = 9.4 \) and \( d_2 = 19 \) into the formula \( A=\frac{1}{2}d_1d_2 \).
\[
A=\frac{1}{2}\times9.4\times19
\]
First, calculate \( 9.4\times19 = 178.6 \). Then, \( \frac{1}{2}\times178.6=89.3 \).

Answer:

The area of rhombus \( BCDE \) is \( 89.3 \).