Question

the given equation relates the resistance r, in ohms, of a wire to its length l, in meters, and its cross - sectional area a, in square meters. which equation correctly expresses the length, in meters, of the wire in terms of its resistance, in ohms, and its cross - sectional area, in square meters? r = 0.43l/a a. l = 0.43 r - a b. l = 0.43 r + a c. l = 0.43r a d. l = 0.43 ar

Explanation:

Step1: Isolate the variable $l$

Given $R = \frac{0.43l}{A}$, multiply both sides by $A$ to get $RA=0.43l$.

Step2: Solve for $l$

Divide both sides of the equation $RA = 0.43l$ by $0.43$. So, $l=\frac{RA}{0.43}$.

Answer:

C. $l=\frac{0.43R}{A}$