Question

given $f(x) = \sqrt3{x}$ and $g(x) = x^3 - 3x + 10$, find $(f \circ g)(1)$.
2
1
8
-8

Explanation:

Step1: Calculate $g(1)$

Substitute $x=1$ into $g(x)$:
$g(1) = 1^3 - 3(1) + 10 = 1 - 3 + 10 = 8$

Step2: Calculate $f(g(1))$

Substitute $g(1)=8$ into $f(x)$:
$f(8) = \sqrt[3]{8} = 2$

Answer:

2