Question

given $f(x) = \sqrt{x}$ and $g(x) = x + 4$, find $(f \circ g)(x)$.$\bigcirc$ $x^2 + 4LXB0\bigcirc$ $f(x) = \sqrt{x + 4}$$\bigcirc$ $f(x) = \sqrt{x + 4}$

Explanation:

Step1: Define composite function

$(f \circ g)(x) = f(g(x))$

Step2: Substitute $g(x)$ into $f$

$f(g(x)) = f(x+4) = \sqrt{x+4}$

Answer:

$\boldsymbol{f(x) = \sqrt{x+4}}$ (the fourth option)