Question

given that $g(x)=x^2 - 2x - 6$, find $(g \circ g)(-3)$.
$(g \circ g)(-3)=\square$ (simplify your answer.)

Explanation:

Step1: Calculate $g(-3)$

$g(-3) = (-3)^2 - 2(-3) - 6 = 9 + 6 - 6 = 9$

Step2: Calculate $g(g(-3))=g(9)$

$g(9) = 9^2 - 2(9) - 6 = 81 - 18 - 6 = 57$

Answer:

57